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x^2-2x-2450=0
a = 1; b = -2; c = -2450;
Δ = b2-4ac
Δ = -22-4·1·(-2450)
Δ = 9804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9804}=\sqrt{4*2451}=\sqrt{4}*\sqrt{2451}=2\sqrt{2451}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{2451}}{2*1}=\frac{2-2\sqrt{2451}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{2451}}{2*1}=\frac{2+2\sqrt{2451}}{2} $
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